Friday, February 16, 2007

Never irritate a engineer!

See below why not…

6 comments:

Anonymous said...

$536.49

Anonymous said...

not true, it's $0.002 or 0.2 cents.
e^(i*pi) = -1
sum of 1/2^n from 1 to infinity is 1

Anonymous said...

You are wrong, e^(i*pi) is a complex number with real part=0.
1/2^n from 1 to infinity is 0.
It's 0.2 cents.

Anonymous said...

no the second comment is really right in the reasoning, third is just wrong

Anonymous said...

Believe me guys. First person was right. It is 0.002 + e^(2*pi) + infinite_sum_starting_in_one_of_(1/2^n). So it's not e^(2*i), nor the infinite_sum adds to zero; just take 1/2 + 1/4 and you'll have 0.75; whole infinite_sum adds to 1. Total check sum = $536.49.

Anonymous said...

Last commentor: Read the check again, the exponent of e is "i*Pi", not "2*Pi".

My 0.2 cents.